(5/6x^2)-(7/3x)=(1/2)

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Solution for (5/6x^2)-(7/3x)=(1/2) equation: 


x in (-oo:+oo)

(5/6)*x^2-((7/3)*x) = 1/2 // - 1/2

(5/6)*x^2-((7/3)*x)-(1/2) = 0

(5/6)*x^2+(-7/3)*x-1/2 = 0

5/6*x^2-7/3*x-1/2 = 0

DELTA = (-7/3)^2-(-1/2*5/6*4)

DELTA = 64/9

DELTA > 0

x = ((64/9)^(1/2)+7/3)/(5/6*2) or x = (7/3-(64/9)^(1/2))/(5/6*2)

x = 3 or x = -1/5

x in { -1/5, 3 }

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